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prob2 added by anonymous on Tue Sep 25 07:15:48 2012

(define (compute a b c)
  (cond ((and (<= a 0) (<= b 0) (<= c 0)) (+ a b c))
	((or (> a (+ b c)) (> b (+ a c)) (> c (+ a b))) (* a b c))
	((or (<= (and a b) 0) (<= (and a c) 0) (<= (and b c) 0)) (square (min a b c)))
	(else (square (max a b c)))
)
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